What must be the acceleration of a train in order for it to stop from 12 m/s in a distance of 541 m

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i just did this and got a 100.

your answer is c! hope this : )

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

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