Acar traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. what was its acceleration? round your answer to the nearest 100th place. answer in units of ft/s^2. what is the final velocity at this time? answer in units of ft/s.

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

Equation of motion

Acceleration is 51.94 ft/s²

Final velocity at this time is 257.63 ft/s

the answer is b ) square root of 5

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever