Amuon has a kinetic energy equal to 4 times its rest energy of 105 mev. (a) what is its velocity, in units of c?
(b) what is its momentum in energy units (i. e., units of mev/c)?

v = 0.9798*c

Explanation:

E0 = 105 MeV

The mass of a muon is

m = 1.78 * 10^-30 kg

The kinetic energy is:

The kinetic energy is 4 times the rest energy.

v^2 / c^2 = 1 - 1/25

v^2 / c^2 = 24/25

v^2 = 24/25 * c^2

v = 0.9798*c

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