Ablock is placed on a plane inclined at 37.0° to the horizontal. the coefficient of kinetic friction is 0.40. if the block is released, what is its acceleration? include a diagram.

2.77 m/s^2

Explanation:

For simplicity, we will say that the x-axis is parallel to the inclined plane and the y-axis is perpendicular to the inclined plane. The force that the surface applies on the block N will be perpendicular to the plane. The force of friction can be expressed like this:

Where u is the coefficient of kinetic friction.

The x-component and y-component of the weight force will be:

In the y-axis, the acceleration of the block is 0. Then:

In the X-axis, the summation of forces would be:

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

answera compound;