Acharge 5.00 nc is placed at the origin of an xy-coordinate system, and a charge -1.97 nc is placed on the positive x-axis at x = 4.00 cm . a third particle, of charge 6.05 nc is now placed at the point x = 4.00 cm , y= 3.02 cm . q: find the y-component of the total force exerted on the third charge by the other two

The total force exerted on the Y axis is: -52.07μC

Explanation:

This is an electrostatic problem, so we will use the formulas from the Coulomb's law:

We are interested only of the effect of the force on the Y axis. We can notice that the charge placed on the x=4cm will exers a force only on the Y axis so:

Fy1=-117.61μC

For the charge placed on the origin we have to calculate the distance and the angle:

we can find the angle with:

The for the Force on Y axis is:

Fy2=65.54μC

The total force exerted on the Y axis is:

Fy=Fy1+Fy2=-52.07μC

connect the batteries in series and hope

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.