Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following accelerations. (a) a = -4.0 m/s^2 (b) a = -8.0 m/s^2

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time,

(a) Acceleration,

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration,

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

33: i think it’s b

there are no atoms