Arocket accelerates straight up from the ground at 12.6 m/s^2 for 11.0 s. then the engine cuts off and the rocket enters free fall. (a) find its velocity at the end of its upward acceleration. (b) what maximum height does it reach? (c) with what velocity does it crash to earth? (d) what's the total time from launch to crash?

a) 138.6 m/s

b) 762.3 m

c) 122.3 m/s

d) 24.47

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Velocity at the end of its upward acceleration is 138.6 m/s

Maximum height the rocket reaches is 762.3 m

The velocity with which the rocket crashes to the Earth is 122.3 m/s

Total time from launch to crash is 12.47+11 = 24.47 seconds

an electric circuit

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force