The flywheel of a steam engine runs with a constant angular speed of 158 rev/min. when steam is shut off, the friction of the bearings and the air brings the wheel to rest in 2.6 h. what is the magnitude of the constant angular acceleration of the wheel in rev/min^2? do not enter the units.

α=1.013rev/min^2

Explanation:

Wo=initial angular speed=158rev/min

t=time=2.6h=156min

Wf=final angular speed=0rev /min  , this happens because in the end the wheel stops

this is a circular motion with uniform acceleration therefore we can use the following equation

α=angular aceleration=(Wf-Wo)/t

α=(0-158)/156=1.013rev/min^2

the higher the current the higher the mag field around it the higher the influence on the compass

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this