Physics, 12.09.2019 23:20, cicilee49

Aball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. the distance s (in feet) of the ball from the ground after t seconds is s=80+64t-16t^2.a) after how many seconds does the ball strike the ground? b) after how many seconds does the ball pass the top of the building on its way down?

Answers: 2

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answered: reimanjr9186

a) t=6.37s

b) t=3.3333s

Explanation:

The knowable variables are the initial hight and initial velocity

$s_{o}=80ft$

$v_{os}=64ft/s$

The equation that describes the motion of the ball is:

$s=80+64t-16t^{2}$

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

$0=80+64t-12t^{2}$

a) Solving for t, we are going to have two answers

$t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

a=-16

b=64

c=80

t=-1.045 s or t=6.378s

Since time can not be negative the answer is t=6.378s

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

$v_{y}=v_{o}+gt$

at maximum point the velocity is 0

0=64-32.2t

Solving for t

t=1.9875 s

Now, we must know how much distance does it take to reach maximum point

$s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft$

So, the ball pass the top of the building on its way down at 160 ft

$160=80+64t-16t^{2}$

Solving for t

t=2s or t=3.333s

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

answered: blakestuhan

(a) 5 s

(b) 4s

Explanation:

height of building, s = 80 feet

The equation of motion is given by

$s=80+64t-16t^{2}$

(a) Let it takes t time to reach the ground. A it reach the ground, s = 0

So, put s = 0 in the given equation, we get

$0=80+64t-16t^{2}$

$t^{2}-4t-5=0$

(t + 1)(t - 5) = 0

t = -1 s, t = 5 s

As time cannot be negative, so t = 5 s

Thus, the time taken by the ball to reach the ground is 5 s.

(b) Let it crosses the building in t second, s put s = 80 feet in the above equation, we get

$80+64t-16t^{2}=80$

t(4 - t)= 0

t = 0s or t 4 s

So, it takes 4 second to cross the building.

answered: Guest

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

answered: Guest

momentum of soft ball three times less than baskey ball

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Aball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity o...