The driver of a car slams on the brakes when he sees a tree blocking the road. the car slows uniformly with acceleration of −5.25 m/s2 for 4.15 s, making straight skid marks 62.5 m long, all the way to the tree. with what speed (in m/s) does the car then strike the tree? you may want to calculate the initial velocity of the car first. m/s (b) what if? if the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2

Part a)

Final speed of the car is

Part b)

Acceleration of the car is

Explanation:

As we know that car makes a skid of 62.5 m

here acceleration of the car is

now we have

Part a)

Speed of the car by which it will hit the tree

Part b)

Now if car will stop after travelling same distance which same initial speed

Then we can use kinematics

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: