Onsider a 20-cm-thick granite wall with a thermal conductivity of 2.79 w/m·k. the temperature of the left surface is held constant at 50°c, whereas the right face is exposed to a flow of 22°c air with a convection heat transfer coefficient of 15 w/m2·k. neglecting heat transfer by radiation, find the right wall surface temperature and the heat flux through the wall.

q=heat flux=216.83W/m^2

Ts=36.45C

Explanation:

What you should do is raise the heat transfer equation from the inside of the granite wall to the air.

You should keep in mind that in the numerator you place the temperature differences, while the denominator places the sum of the thermal resistances by conduction and convection.

When you have the heat value, all you have to do is use the convection equation q = h (ts-t) and solve for the surface temperature.

I attached procedure

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

b.a device that inputs heat into a cool object