2. calculate the average magnitude of the force of gravity on the planet neptune (mass of 1.02*10^ 26 kg) due to the sun (mass of 1.99*10^ 30 kg) , assuming an average orbital distance of 4.50*10^ 12 m.

The answer to your question is: F = 6.69 x 10²⁰ N

Explanation:

To solve this problem we need to use the Newton's law of universal gravitation.

F = G(m1m2)/r²

where

F = ?

G = 6.674×10−11 N · (m/kg)2  is the gravitational constant

m1 = Neptune mass = 1.02 x 10²⁶ kg

m2 = Sun mass = 1.99 x 10³⁰ kg

r orbital distance among the planets = 4.50 x 10¹² m

Substitution

F = 6.674×10−11 N · (m/kg) x 1.02 x 10²⁶ kg x 1.99 x 10³⁰ kg / (4.50 x 10¹² m)²

F = 1.355 x 10⁴⁶ / 2.025 x 10²⁵

F = 6.69 x 10²⁰ N

you have to draw the persons position over there

0.55x745.7j and a calculator