An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is time, y is the height at that time, y0 is the initial height (at t=0), v0 is the initial velocity, and g=9.8m/s2 (the acceleration due to gravity). if you stand at the edge of a cliff that is 75 m high and throw a rock directly up into the air with a velocity of 20 m/s, at what time will the rock hit the ground? (note: the quadratic formula will give two answers, but only one of them is reasonable.)
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Mathematics, 14.07.2019 05:00, deejayjaytee
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Physics, 09.09.2019 22:30, brennarfa
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Mathematics, 23.10.2019 03:30, jholland03
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An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is t...
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