In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. let's say we now have
3c+4d=5
2c+5d=2
none of these terms has a coefficient of 1. instead, we'll pick the variable with the smallest coefficient and isolate it. move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. which of the following expressions would result from that process?
c=53−43d
c=1−52d
d=25−25c
d=54−34c
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correct
part e - solving for two variables
now that you have one of the two variables in part d isolated, use substitution to solve for the two variables. you may want to review the multiplication and division of fractions and simplifying an expression primers.
enter the answer as two numbers (either fraction or decimal), separated by a comma, with c first.
need the answer with work shown for part e.
in advance

answer: what are you talking about?

explanation:

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

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