Acar traveling at a speed of v can brake to an emergency stop in a distance x , assuming all other driving conditions are all similar , if the traveling speed of the car double, the stopping distance will be (1) √2x,(2)2x, or(3) 4x: (b) a driver traveling at 40.0km/h in school zone can brake to an emergency stop in 3.00m. what would be braking distance if the car were traveling at 60.0 km/h?
Answers: 2
![= 4[\frac{1}{2}mv^2] = 4fx](/tpl/images/0226/4624/8c105.png)
![f*3 = [\frac{1}{2}mv^2] = [\frac{1}{2}m*11.11^2]](/tpl/images/0226/4624/093c4.png)
![f*D = [\frac{1}{2}m*16.66^2]](/tpl/images/0226/4624/d67bc.png)
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