The height of a helicopter above the ground is given by h = 3.30t3, where h is in meters and t is in seconds. at t = 2.30 s, the helicopter releases a small mailbag. how long after its release does the mailbag reach the ground? 9.857 incorrect: your answer is incorrect.

The total time to reach ground is 24.89 seconds

Explanation:

Since the height of the helicopter is given by

thus at time t = 2.30 seconds the height of the helicopter is

The velocity of helicopter upwards at time t = 2.30 is given by

Now the time after which it becomes zero can be obtained using the equations of kinematics as

1) Time taken by the mailbag to reach highest point equals

2) Time taken by the mailbag to reach ground from a height of 40.151 meters equals

Solving for t we get

Now the total time of the journey is

ill do it for 100, also this isnt 80 its 40

be subject to a force andchange its motion