Physics
Physics, 09.09.2019 17:30, sshaynijaonnahayde

In the theory of relativity, the mass of a particle with velocity v is m = \frac{m_0}{\sqrt{1 - v^2/c^2}}, where m₀ is the mass of the particle at rest and c is the speed of light. what happens as v → c⁻?
a. m → m₀
b. m → 1
c. m → 0
d. m → m⁻

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Answers: 3

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In the theory of relativity, the mass of a particle with velocity v is [tex]m = \frac{m_0}{\sqrt{1 -...

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