Wile e. coyote (carnivorous hungribilous) is chasing the roadrunner (speedibus cantcatchmi) yet again. while running down the road, they come to a deep gorge, 15 m straight across and 100 m deep. the roadrunner launches itself across the gorge at a launch angle of 15° above the horizontal, and lands with 1.5 m to spare.
(a) what was the roadrunner's launch speed? ignore air resistance.
(b) wiley coyote launches himself across the gorge with the same initial speed, but at a different launch angle. to his horror, he is short the other lip by 0.5 m. what was his launch angle? (assume that it was lower than 15°.)

(a)

(b)

Explanation:

Let´s use the maximum horizontal distance traveled by a projectile formula:

(1)

So, we know that the maximum distance reached by the Roadrunner is:

=16.5m

if we assume that:

replacing the values in (1)

Using the maximum horizontal distance traveled by a projectile formula again, let´s calculate the maximum distance reached by the Coyote:

=14.5m

Assuming

and replacing in (1)

centigrades

and 1and 1

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.