An object of 8 cm height is 15 cm in front of a converging lens with focal length of magnitude 4 cm. what is the dimension of the image? do not include the sign)?

image height is 2.9 cm

Explanation:

We have given the size of the object O = 8 cm

Distance of the object from the lens = 15 cm

Focal length of the lens = 4 cm

Now for lens we know that

So

v = 5.454 cm

Now magnification

Now magnification is the ratio of image height and object height

So , where I is the height of image and O is the height of object

So

I =2.9 cm

force tends to be low and long diustance masses are high