At one instant in time an lr circuit has a current flowing through it of 44ma. at a time 3.3 us later the current is 22ma. the resistor is 1.0 megaohm. what is the inductance of the inductor? a) 1.1 h b) 2.5 h c) 3.1 h d) 4.8 h

d.7.5cm is your answer

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j