Light of wavelength 610 nm falls on a slit that is 3.50×10^−3 mm wide. how far the first bright diffraction fringe is from the strong central maximum if the screen is 10.0 m away.
express your answer to three significant figures and include the appropriate units.

2.6143 m

Explanation:

For constructive interference, the expression is:

d is the distance between the slits.

The formula can be written as:

....1

The location of the bright fringe is determined by :

Where, L is the distance between the slit and the screen.

For small angle ,

So,  

Formula becomes:

Using 1, we get:

For the single slit diffraction, the bright fringes are represented by the half-integers. The first such integer is, m = 1.5

y = ?

Given L = 10.0 m

d = 3.50 × 10⁻³ mm

Also, 1 mm = 10⁻³ m

So, d = 3.50 × 10⁻⁶ m

λ = 610 nm  

Since, 1 nm = 10⁻⁹ m

So,  

λ = 610 × 10⁻⁹ m

Applying the formula as:

⇒ y, location of first bright fringe = 2.6143 m

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

a=d/t

a="triangle"v/t

explanation:

a = acceleration