What is the relation between the wavelength, λ, and the momentum, p, of a particle? roughly what kinetic energy should an electron have in order for its wavelength be of roughly an "atomic" distance scale? re-express this as the number of volts needed to accelerate that electron from rest to this energy. would you call this a high-voltage device?

λ = h/p

This energy is equivalent to E=150.44eV

Explanation:

de Broglie Equation:

λ = h/p

h=6.63×10-34 m2 kg / s        Planck's constant

so: p=h/λ

On the other hand, an atomic distance, an angstrom, is equal:, λ should be similar to this distance.

Kinetics Energy of a electron, m=9.11×10−31 kg

Number of volts needed to accelerate that electron from rest to this energy:

So, this energy is equivalent to E=150.44eV

This high-voltage device is called: particles accelerator

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.