Astone is thrown vertically into the air from a tower 110 ft. high at the same time that a second stone is thrown upward from the ground. the initial velocity of the first stone is 60 ft/s and that of the second stone 85 ft/s. when and where will the stones be at the same height from the ground?

The stones will be at the same height of 62.59 feets 4.4 seconds later.

Explanation:

We will be using the following kinematic equation for 1D movement:

.

For the first stone we got:

,

of course, taking the gravitational acceleration

.

For the second stone we got:

.

.

Now, we want to find the time t' at which both stones will be at the same height, this is

.

So

.

Working a little the equation

Now, to find where the stones will be, we can just replace t for t' in any of the two formulas for the stones:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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