Two 3.7 microcoulomb charges are 0.8 m apart. how much energy (in millijoule) went into assembling these two charges? enter a number with one digit behind the decimal point.

Explanation:

The potential energy of a system of two charges is given by the expression

Q₁ and Q₂ are two charges and R is distance between the charges.

Given Q₁ = Q₂ = 3.7 X 10⁻⁶ , R = .8 and K = 9 x 10⁹

Putting these values in the equation we have,

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Potential energy = 154.01 x 10⁻³ J

This energy have been spent to bring these repelling two charges at this close distance . The energy spent have been stored as potential energy here which has been calculated.