The heat of fusion of water is 6.01 kj/mol. the heat capacity of liquid water is 75.3 j/mol · k. the conversion of 50.0 g of ice at 0.00°c to liquid water at 22.0°c requires kj of heat.

kJ

Explanation:

= mass of  1 mole of water = 18 g

= given mass of water = 50 g

Number of moles of water in the given amount is given as

= Heat of fusion of water = 6.01 kJ/mol = 6010 J/mol

= specific heat of water = 75.3 J/mol

= Change in temperature = 22.0 °C

Amount of heat required is given as

J

kJ

The quantity of heat required to convert the given ice into liquid water at the given temperature is 21,297.82 J.

The given parameters;

The quantity of heat required to convert the given ice into liquid water at the given temperature is calculated as;

Thus, the quantity of heat required to convert the given ice into liquid water at the given temperature is 21,297.82 J.

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answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.