Physics, 04.09.2019 16:30, Ain805

Xrays have wavelengths on the order of 1 3 10210 m. calcu‑ late the energy of 1.0 3 10210 m x rays in units of kilojoules per mole of x rays. (1 mol x rays 5 6.022 3 1023 x rays.) am radio waves have wavelengths on the order of 1 3 104 m. cal‑ culate the energy of 1.0 3 104 m radio waves in units of kilo‑ joules per mole of radio waves. consider that the bond energy of a carbon–carbon single bond found in organic compounds is 347 kj/mol. would x rays and/or radio waves be able to disrupt organic compounds by breaking carbon–carbon single bonds?

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answered: codycollier

Answers:

a) $E_{Xrays}=1.19(10)^{6} kJ/mol$

b) $E_{AM}= 1.19(10)^{-8} kJ/mol$

c) X rays have the energy to disrupt organic compounds by breaking carbon–carbon single bonds, but AM radio waves not.

Explanation:

The energy of a photon in Joules is given by the following formula:

$E=\frac{hc}{\lambda}$ (1)

However, if we want to know this energy in units of J/mol , we have to use the following formula:

$E=\frac{hc}{\lambda} NA$ (2)

a) Now, in the case of X rays:

$E_{Xrays}=\frac{hc}{\lambda_{Xrays}} NA$ (3)

Where:

$E_{Xrays}$ is the energy of X rays in Joules ()

$h=6.6260701509 (10)^{-34} J.s$ is the Planck constant

$c=3(10)^{8}m/s$ is the speed of light

$\lambda_{Xrays}=1(10)^{-10}m$ is the wavelength of X rays

$NA=6.0221(10)^{23}/mol$ is the Avogadro's number

$E_{Xrays}=\frac{(6.6260701509 (10)^{-34} J.s)(3(10)^{8}m/s)}{1(10)^{-10}m}(6.0221(10)^{23}/mol)$ (4)

$E_{Xrays}=1.19(10)^{9}J/mol=1.19(10)^{6} kJ/mol$ (5) This is the energy of X rays in units of kilojoules per mole

b) For AM radio waves:

$E_{AM}=\frac{hc}{\lambda_{AM}} NA$ (6)

Where:

$E_{AM}$ is the energy of AM radio waves in Joules ()

$\lambda_{AM}=1(10)^{4}m$ is the wavelength of AM wavelength

$E_{AM}=\frac{(6.6260701509 (10)^{-34} J.s)(3(10)^{8}m/s)}{1(10)^{4}m} 6.0221(10)^{23}/mol$ (7)

$E_{AM}=1.19(10)^{-5} J/mol= 1.19(10)^{-8} kJ/mol$ (8) This is the energy of AM radio waves in units of kilojoules per mole

c) Which is able to disrupt carbon–carbon single bonds?

If we compare the energy of both (X rays and AM radio waves) with the energy of a carbon–carbon single bond ( 347 kJ/mol ), we will have the following:

$1.19(10)^{6} kJ/mol 1.19(10)^{-8} kJ/mol 347 kJ/mol$

This means the energy of X rays is greater than the energy of AM radio waves and greater than the energy of carbon–carbon single bond as well:

$E_{Xrays} E_{AM} E_{carbon}$

In addition, this means X rays have the energy to disrupt organic compounds by breaking carbon–carbon single bonds, but AM radio waves not.

answered: Guest

The horse latitudes-high-pressure zones about 30 degrees north and 30 degrees south of the equator.-warm air traveling away from the equator cools and sinks-weather tends to be clear and drythe doldrums-low-pressure near equator-air rises and spreads out toward the poles-rising moist air produces clouds and heavy rainthe westerlies-blow from the west-move from the horse latitudes toward the poles.-bring storms across much of the united statesthe tradewinds-blow from the east-move from the horse latitudes toward the equator -strong, steady winds

answered: Guest

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.

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Xrays have wavelengths on the order of 1 3 10210 m. calcu‑ late the energy of 1.0 3 10210 m x rays i...