Acar travels in the positive direction from point a to point bin 3.0 hours. the car then
returns to point a during the next 5 hours. points a and b are separated by 25 km.
which of the following statements are correct?
*select all that apply.
the car's average velocity on the final leg (from point b to a) of the trip is 1.39 m/s.
the car's average velocity for the entire trip is +1.7 m/s.
the car's average speed for the entire trip is 0.87 m/s.
the car's average velocity for the entire trip is o m/s.
the car's average speed for the entire trip is 1.7 m/s.

The following statements are correct:

a) The car's average velocity on the final leg (from point B to A) of the trip is 1.39 m/s.

b) The car's average velocity for the entire trip is O m/s.

c) The car's average speed for the entire trip is 1.7 m/s.

Explanation:

a) We can calculate the car's average velocity of the final leg as:

v = d / t = 25 km / 5 h = 5 km/h = 5 . 1000 m / 3600 s = 1.39 m/s

where:

v: velocity in the final leg

d: displacement in the final leg

t: time of the travel from point B to point A

b) The car's average velocity for the entire trip is O m/s because the car is at same place at the end and at the beginning of the full travel.

v = d / t = 0 km / 8 h = 0 km/h = 0 . 1000 m / 3600 s = 0 m/s

where:

v: velocity in the entire travel

d: displacement in the entire travel

t: time of the entire travel

c) We can calculate the car's average speed for the entire trip as:

s = Δd / Δt = (d₁ + d₂) / (t₁ +t₂) = (25 km + 25 km) / (3h + 5h) = 50 km / 8h) =  6.25 km/h . 1000 m/km / 3600 s/h = 1.7 m/s

where:

s: speed in the entire travel

Δd = distance of the entire travel

Δt =  time of the entire travel

d₁= distance of the first part of the travel (from A to B)

d₂=  distance of the second part of the travel (from B to A)

t₁= time of the first part of the travel (from A to B)

t₂= time of the second part of the travel (from B to A)

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.