Determine the heat energy required to vaporize 13.9 grams of liquid water at 100° c. o 2,006 cal o 47.8 cal o 7,506 cal o 24.9 cal

7506 cal

Explanation:

Given: Mass of water = m = 13.9 grams.

Heat energy required to determine the conversion of 13.9 grams of water to steam or vapor is m L,

where L = Latent heat of vaporization of water=540 cal/g.

Q = mL = (13.9)(540) = 7,506 cal.

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