5. paul is driving a car at a constant velocity of 8 m/s (about 18 mi/hr.) he sees a cat in the road ahead and brakes.
his car accelerates at a rate of -4 m/s/s. how long will it take for his car to stop?
a 28
b. 45
c. 1.26 s
d. 88

2 seconds

Explanation:

We need to use the kinematic equation vf-vi+at and rearrange it to find t.

(if you need help rearranging this question then let me know)

but fully rearranged it's:

vf-vi / a = t

so:

0-8 ÷ -4 = 2

(vi-vf is in brackets, then divided by -4)

If you want to check the answer when you rearrange just take the answer and use it in the unrearranged kinematic equation. So if this was rearranged correctly vf sound equal 0 (use 2 for time)

2 sec

Explanation:

a = v - u / t

-4 = 0 - 8 / t

-4 = -8 / t

-4 / -8 = t

2 sec = t

prndulum needs thread, weight clock to time swings