Assume that the brakes in your car create a constant deceleration of 3.4 m/s2 regardless of how fast you are driving.
calculate the stopping distances for initial speed of 38 m/s .
so, i put it in the equation vf^2=vi^2+2aδx and i got the answer 212.35 but they only want 2 significant figures which means i can only put 21 but its wrong so i ma a little

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

it is a negative acceleration