Air at 38oc and 97% relative humidity is to be cooled to 14oc and fed into a plant area at a rate of 510 m3/min. calculate the rate (kg/min) at which water condenses. (round the answer to the nearest whole number)

mass flow rate at  water condenses is 36.72 kg/min

Explanation:

given data

temperature t1 = 38°C

temperature t2 = 14°C

humidity ∅= 97 % = 0.97

rate v = 510 m³/min

to find out

mass flow rate at  water condenses

solution

by gas equation we find here mass flow rate  that is

pv = mRT

put here value and p is 0.066626 bar at 38°C and find m

m = 0.06626 × × 510  / 287×311

m = 37.85 kg/min

so at water condenses mass flow rate is express as

∅ = M / m

Mass flow rate M = ∅ × m

M = 0.97 × 37.85

mass flow rate = 36.72 kg/min

so mass flow rate at  water condenses is 36.72 kg/min

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j