Agas charged accumulator is to provide an hydraulic system with 28 litres of oil from a maximum pressure of 40 mpa to a final pressure of 35 mpa. the accumulator will initially be charged to a pressure of 30 mpa. determine the total volume of the accumulator. assume expansion and compression takes place adiabatically and y 1,4

total volume is 0.9125 m³

Explanation:

given data

oil = 28 litres

pressure p = 40 MPa

final pressure p2 = 35 MPa

initial pressure p1 = 30 MPa

y = 1,4

to find out

volume of accumulator

solution

so we here say that volume of oil

v3 - v2 = 28 litres

so v3 = 0.028 + v2          ......................a

and volume formula is

v1 = v2   ...................1

so v2 = v3    ..............2

put here value in equation  2

v2 = (0.028 + v2)

v2 = 0.274 m³

and here v1 will be

v1 = 0.274  

v1 = 0.3365 m³

and v3 will be

v3 = 0.028 + v2

v3 = 0.028 + 0.274

v3 = 0.302 m³

so

total volume is v1 + v2 + v3

total volume = 0.274 + 0.3365 + 0.302

total volume is 0.9125 m³

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2