In a photoelectric experiment, you shine light onto an electrode and record a current of 25 μa. when you apply +500 mv to the electrode, the current drops to 19 μa. what is the stopping potential magnitude in v?

2.083 V.

Explanation:

Stopping potential is the potential that is required to stop the current to zero . This potential is applied externally to oppose the potential created by the photoelectric effect . It gives the measure the photoelectric potential being generated .

Here current drops to 25 μA to 19 μA by a potential of 500mV

Change in current

= 25 - 19 = 6 μA

Voltage requirement for unit reduction in current

= 500 / 6 μA

To reduce current 0f 25 μA

requirement of V = (500 / 6 )  x 25 =   2083.33 mV = 2.083 V.

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length