Atuning fork vibrating at 509 hz falls from rest and accelerates at 9.80 m/s^2. how far below the point of release is the tuning fork when waves of frequency of 486 hz reach the release point? (take the speed of sound in air to be 343 m/ i need answer in meters.

25.873 m

Explanation:

Original frequency

Acceleration due to gravity =9.80 m/s^2

Observed frequency

When the source is receding from stationary observer then

Distance tuning fork has fallen to reach this speed

Time required to reach the sound to the observer

t=0.071 s

During this time fork has traveled an additional distance of

c

explanation:

continuous conducting path for current, power supply