Betty (mass 40-kg), standing on a frictionless ice patch, catches her leaping dog imass 1s-kgl which is moving directly horizontally, at 3.0 m/s. answer the following questions a. compute betty's momentum before collision with her doggie. 8. compute the momentum of her dog before collision c. compute the direction and the speed of betty and her dog after collision it takes betty 0.2 s to secure the dog in her arms, compute the force with which the dog hit betty. d.

the answer is kevlar

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft