Steam enters an adiabatic turbine at 10 mpa and 500oc and leaves at 10 kpa with a quality of 50.027 percent. neglecting the changes in kinetic and potential energies, determine the power output in mw using 3 decimals for mass flow rate of 15.469.

power output = 30730.71 kJ/s

Explanation:

given data

pressure  p1 = 10 MPa

temperature = 500° C

pressure p2 = 10 kPa

quality = 50.027 % = 0.50027

mass flow rate m = 15.469

to find out

power output in MW

solution

we know energy balance equation here that is

Energy (in) = Energy (out)

mh1 = P(out) + mh2  

P(out) = - m ( h2 - h1)  1

we know here h1 from steam table that is

h1 = 3375.1 kJ/kg and

hf = 191.81 and hfg = 2392.1 kJ/kg

h2 = hf + quality hfg

h2 = 191.81 + 0.50027 (2392.1) = 1388.50 kJ/kg

so from equation 1 we get power output

P(out) = - m ( h2 - h1)

P(out) = - 15.469 ( 1388.50 - 3375.1 )

power output = 30730.71 kJ/s

true, as the earth rotates the sun hits the surface of the planet; causing the day and night cycle.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6