Aspaceship is moving at 0.74 c (0.74 times the speed of light) with respect to the earth. an observer on the spaceship measures the time interval between two events as 30 hrs. if the spaceship had been moving with a speed of 0.86 c with respect to the earth, what would the time interval between the events have been? dt0.86 c = hrs

The time interval is 22.76 hr.

Explanation:

Given that,

Time = 30 hrs

Speed = 0.74c

We need to calculate the time interval measured in earth frame

Using formula of time dilation

Where, = time interval measured in earth frame

=proper time interval

Put the value into the formula

We need to calculate the proper time interval when the velocity is 0.86c

Using formula of time dilation

Hence, The time interval is 22.76 hr.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

2b2t

explanation:

2b2t