Aspaceship is moving at 0.74 c (0.74 times the speed of light) with respect to the earth. an observer on the spaceship measures the time interval between two events as 30 hrs. if the spaceship had been moving with a speed of 0.86 c with respect to the earth, what would the time interval between the events have been? dt0.86 c = hrs

The time interval is 22.76 hr.

Explanation:

Given that,

Time = 30 hrs

Speed = 0.74c

We need to calculate the time interval measured in earth frame

Using formula of time dilation

Where, = time interval measured in earth frame

=proper time interval

Put the value into the formula

We need to calculate the proper time interval when the velocity is 0.86c

Using formula of time dilation

Hence, The time interval is 22.76 hr.

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.