Apot of water is boiling under one atmosphere of pressure. assume that heat enters the pot only through its bottom, which is copper and rests on a heating element. in two minutes, the mass of water boiled away is m = 4.5 kg. the radius of the pot bottom is r = 6.5 cm and the thickness is l = 2.0 mm. what is the temperature of the heating element in contact with the pot?

Explanation:

It is given that,

Mass of boiled water, m = 4.5 kg

Radius of the pot bottom, r = 6.5 cm = 0.065 m

Thickness of the pot, t = 2 mm = 0.002 m

We need to find the temperature of the heating element in contact with the pot.

Heat transferred is from pot to water is given by :

T₁ is the boiling temperature of water, T₁ = 100⁰ C

, q = m L, L is the latent heat of vaporization

,

k is the thermal conductivity of water,

Hence, this is the required solution.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation: