10ω resistor and a 5 ω are connected in parallel. this pair is then connected in series in with another 4 ω resistor. what is the equivalent resistance of the circuit?

7.33 Ω

Explanation:

10Ω resistor and a 5 Ω are connected in parallel

so,

R₁=(10X5)/(10+5)

   =(50/15) Ω

   =3.33 Ω

This pair is then connected in series in with another 4 Ω resistor

R₂=R₁+4

    =(3.33+4) Ω

    =7.33 Ω

explanation:

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