Consider light that has its third minimum at an angle of 23.3° when it falls on a single slit of width 4.05 μm. find the wavelength of the light in nanometers.

The wavelength of light is 533 nm.

Explanation:

It is given that,

Width of a single slit,

Light has its third minimum at an angle of 23.3° when it falls on a single slit. For destructive interference, the equation for minima is given by:

Here, n = 3

So, the wavelength of the light is 533 nm. Hence, this is the required solution.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.