Two charges of -4.0 μc and -5.0 μc are held fixed at the lower two corners of an equilateral triangle of side length 2.0 m, in a vacuum. how much energy to move a point charge of +3.0 μc from a point midway between the other two charges is requi apex of the triangle?

Joules

Explanation:

= length of each side of triangle = 2 m

= initial distance of charge from other two charges at the lower two corners = (0.5) L = (0.5) (2) = 1 m

= final distance of point charge from other two charges at the apex of triangle = 2 m

= point charge = 3 x 10⁻⁶ C

= one of the charge on lower two corners = - 4 x 10⁻⁶ C

= other charge on lower two corners = - 5 x 10⁻⁶ C

= Energy required to move the point charge

Energy required to move the point charge

Joules

answer; (arch); good luck

come closer and become far apart and become steam/gas