Standing on a mountain, you look towards another mountain 6.00 km away, on which there are two persons standing 1.00 meter apart. if the pupil of your eye has a diameter of 3.50 mm, will you be able to resolve the two persons (or will you see them as one). take wavelength of light = 600 nm

No.

Explanation:

We shall solve this problem by calculating the resolving power of eye for given wavelength

Resolving Power of eye = \frac{1.22\lambda }{D}

Where λ is wave length of light and D is diameter of eye.

λ is 600 nm and D is 3.5 mm . Put these values in the given formula

Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\

=209.14 \times 10^{-6}radian

From the formula

Φ = \frac{L}{D}[/tex]

Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .

209.14  \times 10^{-6}=\frac{L}{6000}\\

L= 1.254 m

So minimum distance that can be resolved is 1.254 m.

learn it on the intertant so you can solve

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.