Asolid steel ball with radius 3.00 cm and an aluminum ring with inner radius 2.98 cm are initially at 20 °c. if the ball and ring are heated together, at what common minimum temperature will the ball fit through the ring? a. 226 °c b. 403 °c c. 461 °c d. 552 °c e. 583 °c

635 degree.

Explanation:

L = L₁ + L₁ X α X ΔT

L is length after expansion , L₁ is length before expansion ,α is coefficient o linear expansion and ΔT is rise in temperature.

For steel , α is 13 x 10⁻⁶ and for aluminium it is 24 x 10⁻⁶. Let common temperature required be T.

Using the formula for steel

L( steel ) = 3 + 3 x 13 x 10⁻⁶ ( T -20)

Using the formula for aluminium

L( Aluminium ) = 2.98 + 2.98 x 24 x 10⁻⁶ x ( T-20)

L( Steel ) = L( Aluminium )

3 + 3 x 13 x 10⁻⁶ ( T -20) =2.98 + 2.98 x 24 x 10⁻⁶ x ( T-20)

T = 635 degree .

the cellphone, they would then know if the killer would have contacted them or always hated them. or if it was a breakup. but if that is not the case, then it would be the clothing. to put in a bullet, it would have to be put in by hands. hands have finger prints which, would have giving you the answer of who done it.

explanation:

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: