Aproton is shot perpendicularly at an infinite plane of charge. the charge density of the plane is +7.65×10^−4 c/m^2. if the proton starts out 1.05 mm from the plane, what must its velocity be so that it screeches to a halt exactly as it reaches the plane?

The velocity is .

Explanation:

Given that,

Charge density of the plane

Distance = 1.05 mm

We need to calculate the electric field due to plane of charge

Using formula of electric field

Put the value into the formula

We need to calculate potential difference

Using formula of potential difference

Put the value into the formula

We need to calculate the work requires to be done to reach the surface of the plane

Using formula of work done

Put the value into the formula

We need to calculate the velocity

Using work energy theorem

Hence, The velocity is .

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