Adiffraction pattern is formed on a screen 130 cm away from a 0.420-mm-wide slit. monochromatic 546.1-nm light is used. calculate the fractional intensity i/imax at a point on the screen 4.10 mm from the center of the principal maximum.

The fractional Intensity = 0.0146

Given:

wavelength of the light,

slit and screen separation difference, D = 130 cm = 1.3 m

distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m

slit width, d = 0.420 mm =

Solution:

To calculate the fractional intensity, we use the given formula:

            (1)

For very small angle:                                        

                                 (2)

where

Using eqn (2):

Now, using eqn (1):

its c i just checked it