An electron moving perpendicular to a uniform magnetic field of 3.2 × 10-2 t moves in a circle of radius 0.40 cm. how fast is this electron moving? (e = 1.60 × 10-19 c, melectron = 9.11 × 10-31kg)

2.25 x 10⁷ m/s

Explanation:

B = magnitude of magnetic field = 0.032 T

r = radius of the circle = 0.40 cm = 0.0040 m

q = magnitude of charge on the electron = 1.60 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of the electron

speed of electron is given as

v = 2.25 x 10⁷ m/s

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~