A86.3 μc charge has a potential of 17.5 v. determine how much kinetic energy, in ev, this charge could have.

9.44 eV

Explanation:

q = Amount of charge = 86.3 μC = 86.3 x 10⁻⁶ C     (Since 1 μC =  10⁻⁶ C)

V = Electric potential of the charge = 17.5 Volts

U = Amount of electric potential energy carried by charge

Amount of electric potential energy carried by charge is given as

U = q V

Inserting the values

U = (86.3 x 10⁻⁶) (17.5)

U = 0.00151 J

U =

U = 9.44 eV

KE = Kinetic energy the charge could have

Using conservation of energy

KE = U

KE = 9.44 eV

pe = weightxheight = 2000x1000=2,000,000joules

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