Fe has the electron configuration [ar]3d64s2. what is the magnitude of the orbital angular momentum for its most energetic electron? √2h võh - v12h v12h 20h

Answer : The magnitude of the orbital angular momentum for its most energetic electron is,

Explanation :

The formula used for orbital angular momentum is:

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is,

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is,

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