Aship on the surface of the ocean receives a sonar echo back from an underwater object. the echo path from the object to the ship is at an angle of 35 degrees above the horizontal and takes 3s to return. (velocity of sound in sea water = 1500m/s). a) what is the distance of the object from the ship? b) what is the depth of the object in the sea?

distance of the object from the ship is 2250 m

depth of the object in the sea is 1289 m

Explanation:

Given data

angle = 35 degrees

Velocity of sound in sea water = 1500 m/s

time = 3 s

to find out

distance of the object and depth of the object

solution

we know that here object make angle 35 degree with ship under the sea

so height from top sea level to object is D and object to sea distance is d

so we can say

2d = velocity × time

2 d = 1500 × 3 = 4500 m

so d = 2250 m

distance of the object from the ship is 2250 m

and

we know

depth = distance × sinθ

depth = 2250 × sin35

depth = 2250× 0.573

depth = 1289 m

depth of the object in the sea is 1289 m