When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water is found to be 60°. what will the critical angle be if the slab is surrounded by air? take the index of refraction for water to be 1.33. a) 40.6 b) 42.5°c) 44.2° d) 45.6°e) 47.3°

40.62°

Explanation:

Case I

Light is travelling from slab (incident medium) into the water (refractive medium) , the critical angle = 60°.

The formula for the critical angle is:

Where,

is the critical angle

is the refractive index of the refractive medium.

is the refractive index of the incident medium.

So,

Given that critical angle = 60°

= 1.33

Applying in the formula as:

Refractive index of the slab = 1.5357

Case II

To find the critical angle when the air is the refractive medium (n=1).

So,

Applying in the formula as:

The critical angle is = sin⁻¹ 0.6511 = 40.62°

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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